Question

an electric bulb is rated 220 V E and 100w when it is operated on 110 V the power consumed will be​

Answer 1

Explanation:

HEY MATE .......

$p = \frac{ {v}^{2} }{r} \\ \\ r = \frac{ {v}^{2} }{p} \\ r = \frac{220 \times 220}{100} = 484 \: ohm \\ \\ the \: current \: flow \: in \: the \: circuit \\ \\ i = \frac{v}{r} (v = supplied \: voltage) \\ \\ i = \frac{110}{484 } \\ \\ = 0.2272a \\ \\ the \: voltage \: drop \: across \: the \: bulb \: \\ \\ pb = \frac{ {v}^{2} }{r} = \frac{110 \times 110}{484} \\ \\ pb = 25w$

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