An electric bulb is rated 220 volt and 100 watt. Power consumed by it when operated on 110 volt is
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Answer:
R=V2/P
= (220)2/100
= 484 Ω
The resistance of the bulb remains constant
if the supply voltage is reduced to 110 V then Vʹ=110 V
the power consumed by it is given by the expression = Vʹ2/R
= (110)2/484 = 25w
Hope this helps you ....!!#
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