Physics, asked by laxman3907f, 15 hours ago

an electric bulb is rated 220V and 100 W . when it is operated on 100 V , the power consumption will be​

Answers

Answered by luckychauhan2006oct
11

Answer:

Mark as a brilliant please

Explanation:

The energy consumed by the appliance is given by the expression

P = VI = V2/R

The resistance of the light bulb can be calculated as follows:

R = V2/P

Substituting the values, we get

R = (220)2/100 = 484 Ω

Even if the supply voltage is reduced, the resistance remains the same. Hence, the power consumed can be calculated as follows:

P = V2/R

Substituting the value, we get

P = (110)2 V/484 Ω = 25 W

Therefore, the power consumed when the electric bulb operates at 110 V is 25 W.

Answered by ParikshitPulliwar
0

Answer:

P = V^2/R  

If V = 220 V we have

100 W = 220^2/R

R = 220^2/100 Ω = 484 Ω. This is the resistance of the bulb.

When V = 110 V, power consumed =  V^2/R = 110^2/484 = 25 W.

So, 25 W power is consumed when it is operated on 110 V.

Explanation:

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