Question

an electric bulb is rated 220V and 100W, what is the resistance and what safe current can be passed through it z/

Answer 1

Answer :-

484 Ω

0.45 A

Explanation :-

Given :

Potential difference (V) = 220 V

Power (P) = 100 W

To find :

Resistance (R)

Electric current (I)

Solution :

P = V²/R

100 = 220²/R

100R = 48400

R = 48400/100

R = 484 Ω

________________________________

V = IR

I = V/R

I = 220/484

I = 0.45 A