an electric bulb is rated 22V and 100W when it operated on 110V the power consumed will be what?
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We know,Power P= V²/R, where V is the rated voltage and R is the resistance
P₁=V²/R, R= V²/P= (22)²/100 = 4.84 Ω
If rated voltage is 110V, Power consumedwillbe
P= V²/R= (110)²/4.84= 2500 W
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