An electric bulb is rated 40w , 220 v. HOW MANY bulbs can be connected in parallel with each other across the two wires of 220 v line if the maximum allowabe current is 6 v
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Current in one bulb = 40÷220
Current in N bulbs = 40N÷220, which must be less than 6.
So,
40N÷220=6
N=6×220÷40
N=33 bulbs
Hope this will help you
I like this ans plz mark as brainlist answer
Current in N bulbs = 40N÷220, which must be less than 6.
So,
40N÷220=6
N=6×220÷40
N=33 bulbs
Hope this will help you
I like this ans plz mark as brainlist answer
Ayus2001:
Plz mark as brainlist
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