an electric bulb is rated 50 W ,200 V if it is operated at 110 V , then power consumed by it is
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as, P = V^2/R
Here, P = 50 W
V = 200 V
Now, R = V^2/P
or,. R = 200×200/50 = 800 ohm
Now, power consumed ,P= 110×110/800
or, P = 121/8 = 15.125 W
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