An electric bulb is rated as 100 W, 200 V. If the bulb is connected across a 100 V supply, then the current drawn by the bulb at this voltage is (Assume no change in resistance)
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Explanation:
The electric power in watts associated with a complete electric circuit or a circuit component represents the rate at which energy is converted from the electrical energy of the moving charges to some other form, e.g., heat, mechanical energy, or energy stored in electric fields or magnetic fields.That is, P=VI where, Pe is the power in watts, V is the voltage in volts and I is the current in amperes.
Therefore, if the power is 100 W and the supply voltage is 200 V, then the
current is I= I P = 100W/200V =1/2A.
Hence, the amount of current the bulb will draw is 1/2 amperes.
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