Question

An electric bulb is rated at 200 V; 100 W. What is its resistance ?
Calculate the energy consumed by 3 such bulbs if they glow
continuously for 10 hours for complete month of November.
Calculate the total cost if the rate is 6.50 per units.
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Answer 1

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Answer 2

The resistance , energy and total cost is $400\ \Omega$ , 3 kW.h and 19.5 respectively.

Given :

Potential difference , V = 200 V .

Power of bulb , P = 100 W .

We need to find the resistance of the bulb.

We know ,

Power ,

$P=\dfrac{V^2}{R}\\\\R=\dfrac{V^2}{P}\\\\R=\dfrac{200^2}{100}\\\\R=400\ \Omega$

Now , we need to find the electric energy consumed by 3 bulbs in 10 hours.

$W=3 \times P\times t\\\\W=3\times 100\times 10\\\\W=3000\ W.h\\\\W=3\ kW.h=3 \ units \ .$

Now, it is given that cost of one unit is 6.50 .

Therefore , total cost , $C=3\times 6.50=19.5$

Hence , this is the required solution .

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