Question

An electric bulb is rated at 220 V,100 W .Find its resistance.

Answer 1

Answer:

484 Ω

Explanation:

we have P=VI.

Substituting I=V/R from ohm's law, the power relationship can be rewritten as P=V²/R

From this formula, the resistance can be calculated as follows.

P= V²/R that is, R=V²/P

The power and voltage are given as100W and 220V.

Therefore, R= 220²/100 = 48400/100 = 484

=484Ω.

Hence, the resistance of the bulb is 484 Ω

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