Physics, asked by kshetrithoiba1, 9 months ago

-
An electric bulb is rated at 220V - 200W. What is the resistance of
the filament?

Answers

Answered by Roshinirao8606

6

Answer:

P=v²/R, v=220

R=?

P=200w

Therefore: 200w=220²v/R

= 200*R=220²

=200R=48400

R=48400/200

R=242ohms

Answered by ParviSharma

0

Explanation:

P=v²/R, v=220

R=?

P=200w

Therefore: 200w=220²v/R

= 200*R=220²

=200R=48400

R=48400/200

R=242ohms

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