An electric bulb is rated at 220V-200W.
What is the resistance of the filament?
Answers
Answered by
7
p=vi
i = p/v
i = 200/220
= 100/110
=10/11
=0.90A
therefore r = v/i
r = 220/0.90
=244.4∩ or ohms
sanjeevsudarsanam:
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Answered by
1
484 ohm by using V*2/W
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