An electric bulb is rated at 60W, 240V. Calculate its resistance. If the voltage drops to 192V, calculate the power consumed and the current drawn by the bulb.(Assume that the resistance of the bulb remain unchanged)
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Answered by
8
Given ;
Power = 60 W
V = 240 V
P = V×I
P = V×(V/R)
P = V^2/R
60 = (240×240)/R
R = 4×24
R = 96 ohm
======================
Now,
V = 192 V
R = 96 ohm ----(as it remain unchanged)
P = ?
P = V^2/R
= (192×192)/96
= 384 W
______________________
Hence the power consumed by the electric bulb is 384 Watt.
Power = 60 W
V = 240 V
P = V×I
P = V×(V/R)
P = V^2/R
60 = (240×240)/R
R = 4×24
R = 96 ohm
======================
Now,
V = 192 V
R = 96 ohm ----(as it remain unchanged)
P = ?
P = V^2/R
= (192×192)/96
= 384 W
______________________
Hence the power consumed by the electric bulb is 384 Watt.
Answered by
6
Answer:hope this might be helpful
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