An electric bulb is rated at 60W, 240V. Calculate its
resistance. If the voltage drops to 192V, calculate
the power consumed and the current drawn by
the bulb. (Assume that the resistance of the bulb
remains unchanged).
Answers
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1
Answer:
R=960ohm P=38.4W I=.2A
Explanation:
P=V²/R
60=240×240/R
R=960ohm
Now
P=V²/R
192×192/960
P=38.4W
I²=P/R
I²=38.4/960
I=0.2A
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