An electric bulb is rated at 60W,240V. calculate resistance. If the voltage drops to 192V,calculate the power consumed and the current drawn by the bulb.(assume that resistance of bulb remains unchanged).
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Answered by
1
Resistance is 4 ohms
Current is 48 amps
Power is 9216 W
Current is 48 amps
Power is 9216 W
Answered by
13
P=60W
V=240V
P=V^2/R
R=V^2/P=240.240/60=960ohms
V=192V
R=960ohm
P=V^2/R=192.192/960=38.4W
P=VI
38.4=192.I
I=0.2A
V=240V
P=V^2/R
R=V^2/P=240.240/60=960ohms
V=192V
R=960ohm
P=V^2/R=192.192/960=38.4W
P=VI
38.4=192.I
I=0.2A
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