Question

An electric bulb marked 100W and 400V. During
consumption the resistance of its filament would be:
(a) 1500 ohm
(b) 1600ohm
(c) 1000 ohm
(d) 2000 ohm
plz give ans with solution​

Answer 1

Given:

power= 100W, Voltage= 400V

P= V^2/R

100W= 400^2/R

So, R= 160000/100

      R= 1600 ohm

Thus, the correct answer is option (b) 1600 ohm.

Hope it helps..

Answer 2

Answer:

Explanation:

P=v²/r=400²/100=160000/100=1600

Answer is 1600ohm