an electric bulb marked 100w and 400v . during consumption the resistance of its filament would be
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Answer:
1.6k ohms is the resistance of the filament.
Explanation:
As we know that Power P=VI
we know P=300w and V=400v
Then I= 300/400 amps =0.75 amps and we know
V=IR then R=V/I =400/0.75 =1.6k ohms
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