Physics, asked by rohankumarsahan508, 1 year ago

An electric bulb marked as 50v 200v is connected across a 100 v supply.The present power of the bulb is

Answers

Answered by dhanurox13
2

The resistance of the bulb R = V x V / W = 200 x 200 / 50 = 800 ohms


The current through bulb at 100 V = 100 / 800 = 0.125A


The present power of the bulb = 100 V x 0.125A = 12.5 W

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