An electric bulb of 1000 Ω and an electric iron of 100 Ω are connected to a source of 220V in series. Calculate the amount of current passing through the bulb and the iron. Also calculate the potential difference across the two terminals of the bulb and the iron.
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Answer:
I=0.0022A
Explanation:
Rb=1000
Re=100
V=220v
I=?
R in serie=?
R= Rb+Re
R=1000+100
R=100000
V=IR
I=V/R=220/100000=0.0022A
V=IR
=0.0022 ×100000
V=220v
Hope its Helful!!
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