an electric bulb of 15 ohm and wire of resistance 10 ohm are connected in series with a 50 volt supply find 1.total resistance 2.total current 3.potential difference across wire and bulb
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Answer:
1) Total resistance = 15 + 10 = 25 ohm
2) Total current = 2 A
3) potential Difference = 50V
Explanation:
V = IR
50 = I x 25
I = 50/25
I = 2 A.
Answered by
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Answer:
1. total resistance= 25ohm
2.total current= 50/25= 2A
3.potential difference across wire=2x10=20V
bulb=2x15=30V
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