Question

an electric bulb of 150ohm is connected with series with a heater of 400ohm if the power supplyis 100v find the current​

Answer 1

So in series final resistance = R1+R2.

So R'=400+150= 550 ohm.

Given power supply is 100 W,

We also know P=I^2*R

I^2= 100/550=0.18

I=0.42 A.

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