An electric bulb of 75 W burns for 4 hours a day. What will be the cost of electricity involved in a month of 30 days at ₹2.5 per unit.
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Answered by
12
Power=75W Time=(4*30hours)=120hours
So, Energy =Power*Time
=75*120
=9000Wh =9kWh
Hence,Cost=2.5*9
=22.5rupees.
So, Energy =Power*Time
=75*120
=9000Wh =9kWh
Hence,Cost=2.5*9
=22.5rupees.
JassRandhawa:
btw its wrong
no its right
plz solve one more
Find the energy in kWh consumed in 10hrs by 4 devices of power 500 W each
Set it as another question so that it helps me earn points... I'll surely help!!!
Answered by
0
Explanation:
Assume a "unit" is a kilo Watt hour (as in the UK)
(75/1000) x 4 x 30 x 2.5 = 22.5
rupees.
Attachments:
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