Question

An electric bulb of 8 watt is lightend for 5 hours per day in 30 days how many units will be consumed

Answer 1

Energy consumed by bulb in one day = 8 × 5 = 40Watt hour

Energy consumed by bulb in 30 days = 40 × 30 = 1200 Watt Hour = 1.2 KW hour

Answer 2

Hlo friend..Cutiepie Here .

Here is ur answer :

Power P of electric bulb = 8 Watt = 8/1000 kW

No.Of hours lighted = 5 hour per day.

Energy e consumed by bulb in 1 day :

$power = \frac{energy}{time}$


$energy \: = power \times time$


$e \: = \: \frac{8}{1000} \times 5$


$e = \frac{40}{1000}$


$e = \frac{4}{100}$


$e = 0.04 \: kwh$


Energy consumed in 30 days = 30 × 0.04

= 1 . 2 kWh.

1 unit = 1 kWh

In 30 days, 1.2 units will be consumed.



HOPE IT HELPS YOU..