Question

An electric bulb of resistance 20 ohm and a resistance wire of 4 ohm are connected in series with a 6 v battery .calculate:-a. total resistance of the circuitb. current through the circuitc. P.D across the electric bulbd. p.d across the resistance wire

Answer 1

total resistance = 20 + 4= 24 ohms
current in circuit = V/R = 6/24 = 0.25 A.
PD across bulb= 0.25*20=5 V
PD across wire=0.25*4=1 V

Answer 2

Given

Battery=6v

R1=20 ohm

R2=4ohm

We know that,

(a) total resistence=R1+R2

=20+4

=24ohm

(b) current in circuit= v/r

=6/24=0.25A

(c) PD across bulb=0.25×20

=5v

(D) PD across wire= 0.25×4

=1v