An electric bulb of resistance 20 ohm and a resistance wire of 4 ohm are connected in series with a 6 v battery . Draw the circuit diagram and
calculate:-a. total resistance of the circuitb. current through the circuitc. P.D across the electric bulbd. p.d across the resistance wire
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Answer:
Total resistance = 20 + 4= 24 ohms
current in circuit = V/R = 6/24 = 0.25 A.
PD across bulb= 0.25*20=5 V
PD across wire=0.25*4=1 V
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