Question

An electric bulb of resistance 20 ohm and resistance wire of resistance 4 ohm are connected in series with a 6 volt battery. Draw the circuit diagram and calculate
i) total resistance of the circuit
ii) current through the circuit
iii) potential difference across the electric bulb.




answer quickly ​

Answer 1

Answer:

Given

Battery=6v

R1=20 ohm

R2=4ohm

We know that,

(a) total resistance =R1+R2

=20+4

=24ohm

(b) current in circuit= v/r

=6/24=0.25A

(c) Potential difference across bulb=0.25×20

=5v

(D) PD across wire= 0.25×4

=1v

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