Question

An electric bulb of resistance 200 Ω draws a current of 0.5 mA . The power of the bulb is​

Answer 1

when we mutiply 200 × 0.5 the answer is 200. 5 and when we add 200+ 0.5 the answer is 100.

Explanation:

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Answer 2

answer. A= 0.5×0.001

=0.0005

Resistance (R) =V/I

= 200ohm/0.0005

=40000

power (p) =V×I

=200ohm×0.0005

= 200watt