Physics, asked by rohan07030636, 8 months ago

An electric bulb of resistance 200 Ω draws a current of 2 ampere. The energy in kWh consumed by burning it for 5 hours is

Answers

Answered by ananya2277

2

Answer:

Hope it helps you mate !!!

Attachments:

Answered by kasikayal2001

0

Answer:4kWh

Explanation:

Power=V*i=(iR)*i

=2*2*200

=800 W =800/1000kW

P=4/5kW

E=P*t

=4/5kW*5hr

=4kWh

Hope it helps you

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