An electric bulb of resistance 200 ohm draws
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Correct question : An electric bulb of resistance 200ohm draw a current of 1 ampere calculate the power consumed by the bulb for 5 hours(in kWh).
Power of the bulb, P = l2R = (1)
2 x 200 ⇒ P = 200 W
Energy consumed by bulb in 5h in burning =
Power x Time = 200 x 5 =
1000 Wh =
1 kWh
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