Question

An electric bulb of resistance 200 ohm draws

Answer 1

Correct question : An electric bulb of resistance 200ohm draw a current of 1 ampere calculate the power consumed by the bulb for 5 hours(in kWh).

Power of the bulb, P = l2R = (1)

2 x 200 ⇒ P = 200 W

Energy consumed by bulb in 5h in burning =

Power x Time = 200 x 5 =

1000 Wh =

1 kWh