Question

An electric bulb of resistance 200 ohm draws a current of 1 ampere. Calculate the power of the bulb and energy in kilowatt hour consumed in burning it for 5 hours

Answer 1

A electric bulb of -
Resistance = 200ohm
Current = 1A
Time = t = 5 hours = 5*60 = 300sec
Power = I²R = 1²*200 = 200W
Energy = Pt = 200*300 = 60,000J
In KWhr = 200*5/1000 =1000/1000 = 1kWhr

Answer 2

An electric bulb of resistance =200 ohm
Current =1A
Time=5 hrs
Power = I 2R
=1×200
=200W
Energy =200/1000
=0.2J
In Kwhr=0.2×5
=1.0Kwh
=1Kwh



HOPE YOU UNDERSTAND