Question

An electric bulb of resistance 200ohm draws a current of 1
a. Calculate the power of the bulb and enery consumed in 5 hours

Answer 1

Answer:

Current given

I = 1 amp

And

Resistance given

R = 200 ohm

Time

T = 5 hrs

we know,

power = W/t

= VQ/t

= I / t

= 1 / 5

= 0.2 KWh

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Answer 2

Answer:

6×10⁴

Explanation:

V=IR

V=1×200

V= 200V

P=VIT

P=200×1×5×60

P=6×10⁴W