Question

An electric bulb of resistance 250Ω draws a current of 1 Ampere. Calculate the power of the bulb the potential difference at its ends and the energy in kWh consumed burning it for 6h​

Answer 1

Explanation:

Power of the bulb,

P = l2R = (1)2 x 200

⇒ P = 200 W

Energy consumed by bulb in 5h in burning

= Power x Time

= 200 x 5

= 1000 Wh = 1 kWh