An electric bulb of resistance 400 Ώ draws a current of 0.5 A. Calculate the power of the bulb and the potential difference at
its ends.
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V=IR
I=.5
R=400
so
V=400×.5
=200V
P=VI
=200×.5
=100
I=.5
R=400
so
V=400×.5
=200V
P=VI
=200×.5
=100
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