An electric bulb of resistance 400 ohm, draws a current of 0.5 ampere. calculate the power of the bulb and the potential difference at its ends.
Answers
Answered by
4
Answer:
power = i^2×r ,,,, p= 0.5×0.5×400 means power is 100 watt and V=i×r then V=0.5×400 ,, V=200 volt
Answered by
3
Answer:
potential difference = 200 volt
power = 100 watt
Explanation:
given
resistance = 400 Ohm
current = 0.5 ampere
potential difference = ?
potential difference = current × resistance
potential difference = 0.5 ×400
potential difference = 200 volt
power = current × potential difference
power = 0.5 × 200
power = 100 watt
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