Question

an electric bulb of resistance 400 ohm draws a current of 0.5 a . find power of the bulb and potential difference

Answer 1

= According to ohm's law
V=I*R
V=0.5 *400
V= 200.0 volt

By applying formula
I= p/v
0.5=p/200
P=200*0.5
P= 100 watt