An electric bulb of resistance 480ohm is connected to220v main.find the amount of electrical energy consumed in 10 seconds.
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Given,
R=480ohm
V=220v
A/Q,
From ohm's law,
V=IR
220=I×480
I=220/480......(1)
we know that,
P=VI
P=220×220/480. (using equation 1)
P=100w. (approx)
Now,
t=10sec.=0.002 hour (approx)
P=100w=0.1kWh.
energy consumed= 0.0002kWh.
Therefore, energy consumed in 10 seconds=0.0002kWh.
R=480ohm
V=220v
A/Q,
From ohm's law,
V=IR
220=I×480
I=220/480......(1)
we know that,
P=VI
P=220×220/480. (using equation 1)
P=100w. (approx)
Now,
t=10sec.=0.002 hour (approx)
P=100w=0.1kWh.
energy consumed= 0.0002kWh.
Therefore, energy consumed in 10 seconds=0.0002kWh.
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