An electric bulb of volume 250 cc was sealed during manufacturing at a pressure of 10−3 mm of mercury at 27°C. Compute the number of air molecules contained in the bulb. Avogadro constant = 6 × 1023 mol−1, density of mercury = 13600 kg m−3 and g = 10 m s−2.
Answers
Answered by
2
The number of air molecules contained in the bulb is 
Explanation:
Given:
Electric bulb Volume , V = 250 cc
Temperature at which fabrication takes place, T = 27 + 273 = 300 K
Mercury height,
Mercury Density ,
Avogadro constant,
Solution:
We know that
Pressure ------------------------------(1)
Using the ideal equation for gas we get
-----------------------------------(2)
Substituting (1) in (2), we get
Now substituting the given values,
Number of Molecules =
Answered by
0
hope it help
Similar questions