Physics, asked by neetphodenge, 6 months ago

An electric bulb rated 100 W, 100 V has to be
operated aross 141.4 V, 50 Hz A.C. supply. The
capacitance of the capacitor which has to be
connected in series with bulb so that bulb will
glow with full intensity is
in this question I want to ask that rated values are rms Or peak and value like 141.4V 50Hz A.C are they peak or ac pls adress this particular question I will definitely mark brainlist ​

Answers

Answered by kishangupta8957
2

Answer:

Power=50w

V=100v

I=

V

P

=.5A

The phase: potential across the capacitor must be lag by 90°

(200)

2

=100

2

+V

2

2

V

c

=173.2V

V

c

=I

c

×x

e

x

e

=346.4Ω

X

c

=

2πf

c

1

C=9.29μf

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