CBSE BOARD XII, asked by neetphodenge, 8 months ago

An electric bulb rated 100 W, 100 V has to be
operated aross 141.4 V, 50 Hz A.C. supply. The
capacitance of the capacitor which has to be
connected in series with bulb so that bulb will
glow with full intensity is
in this question I want to ask that rated values are rms Or peak and value like 141.4V 50Hz A.C are they peak or ac pls adress this particular question I will definitely mark brainlist ​

Answers

Answered by shamimsh355
1

Answer:

Power=50w

Power=50wV=100vI=VP=.5A

Power=50wV=100vI=VP=.5AThe phase: potential across the capacitor must be lag by 90°

Power=50wV=100vI=VP=.5AThe phase: potential across the capacitor must be lag by 90°(200)2=1002+V22Vc=173.2VVc=Ic×xe

Power=50wV=100vI=VP=.5AThe phase: potential across the capacitor must be lag by 90°(200)2=1002+V22Vc=173.2VVc=Ic×xexe=346.4ΩXc=2πfc1C=9.29μf

Explanation:

thank you

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