Question

an electric bulb rated at 200v 100w what is its resistance . calculate the energy consumed by three such bulbs if they glow continusly for 10 hours for complete month of November.​

Answer 1

Explanation:

R=V2/P

=400

energy cinsumed=V2/R*T

=400*36000s

Answer 2

Answer:

The resistance of bulb is 400 ohm ,

The energy consumed by three such bulb is 3000 joule

Explanation:

Given as :

rating of electric bulb

Voltage = 200 v,

Power rating = p = 100 watt

Let The resistance =  R ohm

According to question

Power = $\dfrac{voltage^{2} }{Resistance}$

100 = $\dfrac{200^{2} }{R}$

or, R = $\dfrac{200^{2} }{100}$

∴   R = 400 ohm

So, The resistance of bulb = R = 400 ohm

Again

Three 100 watts bulb glow for 10 hours

Let The energy consumed by bulbs = E joule

So, As the bulbs connected in parallel

So, Total power = P = $P_1 + P_2 + P_3$

Or, P = 100 w + 100 w + 100 w

∴ power consumed = 300 watt

Now,

Energy consumed = Power × time

i.e E = 300 × 10

∴ Energy = 3000 joule .

Hence, The resistance of bulb is 400 ohm ,

And The energy consumed by three such bulb is 3000 joule . Answer