Question

An electric bulb rated for 200 w and 100v is connected to a circuit having 200 v supply . This resistance 'r' that must be in series with the blub ,so that the blub draws 200w is

Answer 1

50 Ω Resistance ' must be in series with the blub ,so that the blub still draws 200w

Explanation:

P = V I

=> 200 = 100 * I

=> I  = 2 A

R = V/I

=> R = 100/2

=> R = 50 Ω

∵ P = I²R

Hence current should be same 2 A

Voltage = 200V

R = 200/2 = 100 Ω

resistance 'r' that must be in series with the blub ,

r = 100 - 50

=> r = 50 Ω

50 Ω Resistance ' must be in series with the blub ,so that the blub still draws 200w

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Answer 2

Answer:

50

Explanation:

resistance

hope it helps you friend