An electric bulb, when connected across a power supply of 220 V, consumes a power of
60 W. If the supply drops to 180 V, what will be the power consumed? If the supply is suddenly
increased to 240 V, what will be the power consumed?
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Power consumed by the bulb = 60 W
Voltage across the circuit = 220V
Resistance of the bulb=?(let it be x ohms)
According to the question, P=V^2/R
=>60=(220)^2/x
=>x=220×220/60 ohms or 2420/3 ohms
Voltage in the second case= 180V
Power consume now= V/R^2 = 180×180×3/2420 W = 40.16 W
Voltage in the third case = 240B
Power consumed now = V^2/R
= 240×240×60/220×220 W = 144×60/121 W
=71.40 W
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