Question

An electric bulb, when connected to a 200 V source, draws a current of 0.40 A. Calculate the power and resistance of the bulb.

CBSE Class X Science SA 2 (3 Marks)

Answer 1

Explanation:

P = VI =200×0.40= 80W

Now , R = V/I = 200/0.40= 2000/4= 500 ohm

Answer 2

Answer:

resistance of the bulb = 500 Ω

power of the bulb. = 80W

Explanation:

electric bulb,  connected to a 200 V source

Current Drawn = 0.4 A

Current = Voltage / Resistance

=> Resistance = Voltage / Current

=> Resistance = 200/(0.4)

=> Resistance = 500 Ω

resistance of the bulb = 500 Ω

Power =,Voltage * Current

=> Power = 200 * 0.4

=> Power = 80 W

power of the bulb. = 80W