An electric bulbbis rated to 220v and 100w .When its iperted at 110 v power cinsumed will be
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In case i,
Power (P)= 100W
Potential difference (V)= 220V
Now, we know,
P=VI (where I is the current)
100=220×I
=I=100/220
=5/11 A
Now in case ii,
Current (I)= 5/11 A (from case i)
Potential difference (V)= 110V
Now, P=VI
=P=110×5/11
=10×5
=50W
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