Question

An electric bulbs draws a current of 8A and works on 250 volt on the average of 8 hours a day ..
a) find the power consumed by bulb ?
b)if the electric Distribution Company charges rupees 5 for 6 kilowatt hour what is the monthly bill for 30 days ?

Answer 1

Answer:

1) P=V×I = 250×8 = 2000watt = 2000/1000=2kw

t= 8×30 = 240hr

2) 1hr = 2kw

240 hr = 2×240 = 480 kWh

5rs= 6kwh

1kwh= 5/6rs

480 kWh= 5/6× 480= 5× 80= 400 rs

480 kWh = 400 rs