Question

an electric charge q moves with a constant velocity v parallel to the line of force of a uniform magnetic field b. the magnitude of force experienced by the charge is

Answer 1

Force F on a charge q moving with a velocity v due to a magnetic field B is given by:
F = q (v x B)
Since v is parallel to B, v x B = 0.
Hence F = 0 N.
Therefore, the magnitude of force experienced by the charge is 0 N.

Answer 2

Answer:

Explanation:Force F on a charge q moving with a velocity v due to a magnetic field B is given by:  

F = q (v x B)

F=qvbsintheta

but here  THETA=0

so force=o