Question

An electric circuit of a battery of an emf two resist of 4ohm and 12ohm in parallel and the combination in series with a 2ohm resistance.If the current through the 4ohm be 0.75A .Find the internal resistance of the battery​

Answer 1

Answer:

(i) Total Resistance =4+6+2=12Ω

I (current in circuit)=

Totalresistance

e.m.f.

=

12

12

=1amp

(ii) Voltage drop Ir=1×2=2volt

Terminal Voltage = emf - Voltage drop

=12−2=10 volts

(iii) Potential difference across 6Ω=IR

=1×6=6V

(iv) Energy spent =I

2

Rt

=(1)

2

×4×60=240J

Answer 2

internal is also 6 ohms .Sokution attached