Question

an electric conductor having resistance of 10 ohm is connected to voltage supply for 2 minutes . calculate the work done by battery if the number of electrons passed through x section are 6.25* 10^20 ..

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Answer 1

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Answer 2

Answer:

Explanation:

Given no. Of electrons 6.25*10^20

1electron carries 1.6*10^-19C

So total charge q=6.25*1.6*10=100C

Now current I =100/120=10/12A

Nw W=I²R*t=(100/144)*10*12=833joule