Question

an electric conductor having resistance of 10 Ohm is connected to voltage supply for 2 minutes. calculate the work done by battery if no of electron passed through x section are 6.25*10^20 ...

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Answer 1

Explanation:

R = 10 Ω

given that N=6.25*10^20 electrons passed,

total charge passed is Q= N * 1.6*10^-19 coulombs

Q = 100 C

so the current is i= Q/(2*60) amperes

i = 100/120 = 5/6 A

Now the power is P = i²*R watt

P = 10*(25/36)

Now work done = power*time = P * (2*60) joules

work done = 833.33 J