Math, asked by akshitasrivastava27, 11 months ago

An electric contractor purchases certain amount of wire. 10% of which is stolen.
After using 85% of the remainder, he had 54 m of it left. How much wire did he
purchase?
300 m
350 m
375 m
400 m

Answers

Answered by help7oo645o984
4

Answer:

w - w10/100 - 90w/100 × 85/100 =54

90w/100 - 90w/100 × 85/100=54

90w/100 ( 1- 85/100) =54

90w/100 × 15/100=54

9w/10 × 1.5/10 =54

13.5w= 5400

w = 54000/135 = 400 meters

Answered by SidhantVerma77
8

Answer:

d) 400 meter

Step-by-step explanation:

Let the length of wire purchased by the electric contractor be x

percentage of wire stolen = 10% of x

= 10/100*x

= x/10

wire remaining = x-x/10

= 10x-x/10

= 9x/10

percentage of wire used = 85% of 9x/10

= 85/100*9x/10

= 153x/200

x-(x/10+153x/200) = 54m

x-(20x+153x/200) =54m

x-173x/200 = 54m

200x-173x/200 = 54m

27x/200 = 54m

x = 54*200/27 = 2*200 = 400 meter(ans).

PLEASE MARK IT AS THE BRAINLIEST ANSWER.

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